-16x^2+x+400=0

Solution for -16x^2+x+400=0 equation:

-16x^2+x+400=0

a = -16; b = 1; c = +400;
Δ = b2-4ac
Δ = 12-4·(-16)·400
Δ = 25601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{25601}}{2*-16}=\frac{-1-\sqrt{25601}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{25601}}{2*-16}=\frac{-1+\sqrt{25601}}{-32}
$